975. Ca²-160 mg/L, Mg 40 mg/L.. Total hardness (as CaCO₃)
160 Explained Total Hardness = 160/20x50+40/12x50
= 566.67 mg/L
= 567 mg/L as CaCO 3
উত্তর সহ কয়েকটি অনুরূপ গুরুত্বপূর্ণ প্রশ্ন
1. Ca 2-160 mg/1, Mg 2-40 mg/L. Total hardness (as CaCO,) কত- 567 mg/L
2. If 5 and H are strength and hardness index of a timber at 12% moisture content, the composite sleeper index, is - (S+10H)/20
3. The maximum permissible hardness for public supplies is - (115 mg/litre
4. One degree of hardness of water means a content of salts of - 14.25 mg/litre