131. Ca 160 mg/L, Mg 40 mg/L. Total hardness (as CaCO3) কত?
Total Hardness = 160/20x50+40/1250 x 50
=566.67 mg/L
= 567 mg/L as CaCO3
উত্তর সহ কয়েকটি অনুরূল অরুত্বপুন প্রশ্ন
1. Ca-160 mg/L, Mg-40 mg/L. Total hardness (as CaCO,) কত- 567 mg/L.
2. If S and H are strength and hardness index of a timber at 22% moisture content, the composite sleeper indes, is-(S+10H)/20.
3 . The maximum permissible hardness for public supplies is-(115 mg/litre
4. One degree of hardness of water means a content of salts of -14.25 mg/litre